Question 111596
please explain.

b^2-2bc+c^2=(b-c)^2
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I'll show you that the right side of the equation is the 
same as the left side:
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(b-c)^2
=(b-c)(b-c)
= b(b-c)-c(b-c)
=b^2-bc-bc+c^2
=b^2-2bc+c^2
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Cheers,
Stan H.