Question 1183428

Logistic equation is y=L/(1+be^(-kt)) and dP/dT=kP(1- (P/L))
L=2000, the carrying capacity.
k=constant of proportionality, or 2.1
Using the first,
t=0; 500=2000/(1+be^0)
500(1+b)=2000
b=3
t=1 season
y(1)=2000/(1+3e^(-2.1)=1462.66 or 1463
y(2)=2000/(1+3e^(-4.2))=1913.90 or 1914



{{{graph(300,300,-3,3,-100,2500,1463,1914,2000/(1+3e^(-2.1x)))}}}