Question 1183427
<br>
Let x = amount invested at 1%
Then 3x+1400 = amount invested at 6%<br>
interest from x at 1% = .01(x)
interest from 3x+1400 at 6% = .06(3x+1400)<br>
The total interest was $939:<br>
{{{.01(x)+.06(3x+1400)=939}}}<br>
Solve using basic algebra....<br>