Question 1183386
6x^2 - 2x + 3 leaves a remainder of 3 when divided by x - p. Determine the values of p.

{{{f)x) = 6x^2 -2x+3}}}
divisor = x-p

f(p) = 6p^2-2p+3
By remainder theorem f(p) =remainder= 3

{{{6p^2-2p+3=3 }}}

{{{6p^2-2p=0}}}

2p(3p-1)=0
p= 0 or 1/3