Question 1183386
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If *[tex \Large f(x)] is divided by *[tex \Large x\,-\,p] leaving a remainder of *[tex \Large \alpha], then *[tex \Large f(p)\ =\ \alpha]


So solve *[tex \Large 6p^2\ -\ 2p\ +\ 3\ =\ 3]


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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