Question 1182835
p hat =178/359=0.4958
80% half-interval is z(0.90)*sqrt(0.4958*0.5042/359); z=1.282
=0.0338
The interval is (0.462, 0.530)
The interval then is 0.462 < mu < 0.530
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0.4958+/- 0.0338 or 0.496+/- 0.034