Question 1183295
A polygon has two interior angles of 120 degrees each and the others are 150 degrees.<pre>

{{{(matrix(11,1,

The,sum,"S,",of,the,interior,angles,of,an,"n-sided",polygon))}}}{{{""=""}}}{{{(n-2)*180^o}}}

240 + 150m = (n-2)180

where n = the number of sides and m = the number of 150° angles.
The number of sides could be 5, then there would be 2 120<sup>o</sup> interior angles,
and 2 150° angles.  The sum would be 540<sup>o</sup>.
The number of sides could be 10, then there would be 2 120<sup>o</sup> interior angles,
and 8 150° angles.  The sum would be 1440<sup>o</sup>.
The number of sides could be 15, then there would be 2 120<sup>o</sup> interior angles,
and 14 150° angles.  The sum would be 2340<sup>o</sup>.
The number of sides could be 20, then there would be 2 120<sup>o</sup> interior angles,
and 20 150° angles.  The sum would be 3240<sup>o</sup>.
The number of sides could be 25, then there would be 2 120<sup>o</sup> interior angles,
and 26 150° angles.  The sum would be 4140<sup>o</sup>.
The number of sides could be 30, then there would be 2 120<sup>o</sup> interior angles,
and 32 150° angles.  The sum would be 5040<sup>o</sup>.



This list could go on and on forever.

Edwin</pre>