Question 1183276
<br>
a = cost of adult ticket
c = cost of child ticket<br>
4a+8c=108
5a+6c=105<br>
Divide the first equation by the common factor of 4<br>
a+2c=27<br>
multiply by 5 to make the number of adult tickets the same as in the other equation<br>
5a+10c=135<br>
Compare the two equations<br>
5a+10c=135
5a+6c=105
4c=30
c=7.50<br>
The cost of each child ticket is $7.50<br>
Substitute in either original equation to solve for the cost of an adult ticket<br>
4a+8(7.50)=108
4a+60=108
4a=48
a=12<br>
The cost of each adult ticket is $12<br>
ANSWERS: adult ticket $12; child ticket $7.50<br>