Question 1183254
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There are in fact many more than two ways to solve a problem like this....<br>
Here is what I would do to solve this, given that the two speeds are "nice" numbers.<br>
The distances to and from work are of course the same, and the ratio of the two speeds is 60:45 = 4:3.  That means the ratio of times spent at the two speeds is 3:4.  So 3/7 of the time he drove at 60mph and 4/7 of the time he drove at 45mph.<br>
Since average speed is total distance divided by total time, his average speed in mph was<br>
{{{(3/7)(60)+(4/7)(45) = (3*60+4*45)/7 = 360/7}}}<br>
ANSWER: his average speed in mph was 360/7 = 51 3/7 or 51.4, to the nearest tenth.<br>