Question 1183225
Find the equation of the line through point (−5,5) and perpendicular to y=59x−4. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).and the next problem is Find the equation of the line through point (−1,2) and perpendicular to x+3y=3. Use a forward slash (i.e. "/") for fractions (e.g. 1/2 for 12).
<pre>{{{highlight(y=-x/59+54/59)}}}. He's WRONG, so: {{{cross(highlight(y=-x/59+54/59))}}}
{{{matrix(1,7, y, "=", 59x - 4, "====>", 59x - y, "=", 4)}}}
{{{matrix(1,3, x + 59y, "=", (x) + 59(y))}}} ------ Switching coordinates, negating NEW y coordinate, and equating to a constant, 
                            calculated using the coordinates of the requested equation
{{{highlight_green(matrix(3,3, x + 59y, "=", - 5 + 59(5), x + 59y, "=", - 5 + 295, x + 59y, "=", 290))}}}
Same concept applies to the 2nd equation that's being sought.