Question 1183216
{{{H[0]:  mu = 100}}}
{{{H[1]:  mu > 100}}}

The statistic to use is {{{t = ((X-bar) - mu)/(s/sqrt(n))}}}, with degree of freedom {{{n-1 = 100 - 1 = 99}}}.

==> {{{t = (106 - 100)/(35/sqrt(100) ) = 1.7143}}}, to 4 d.p.

==> {{{P(t > 1.7143) = 0.0448}}}.  This is also the p-value for the test.

Since p-value = 0.0448 > 0.01 (the significance level), we don't reject the null hypothesis, and conclude that the population mean is still 100.

(Probabilities were obtained from https://stattrek.com/online-calculator/t-distribution.aspx)