Question 1180871
(a)  {{{int((4a-2x)/(3a^2), dx, t[1],t[2]) = (1/(3a^2))* int((4a-2x), dx, t[1],t[2])}}},  where {{{0 <= t[1] <= t[2] <= a}}}


(b) {{{(1/(3a^2))* int((4a-2x), dx, a/6,a/3)

= (1/(3a^2))*(4ax - x^2)[a/6]^(a/3)

= (1/(3a^2))*(4a^2/3 - a^2/9 - 2a^2/3 + a^2/36)

=(1/(3a^2))*(21a^2/36) = 7/36



}}}