Question 1183123
Ho:p=0.02
Ha:p NE 0.02
z=(p hat-p)/sqrt(p(1-p)/300)
critical value is z(0.995) so reject Ho for |z|>2.576
=.02/sqrt(.02*0.98/300)
z=2.474; p-value 0.0134 for 2 way test.
Fail to reject at the 1% level; insufficient evidence.
With a Poisson approximation with parameter 6 (300*0.02) the probability of having 12 would be 0.0112.