<PRE><B>Question 1183180</B>
&lt;br&gt;
First, informally....&lt;br&gt;
If Angela is 16 years older than Aaron, then she was twice as old as him when their ages were 32 and 16.
Since that was 8 years ago, their ages now are 40 and 24.&lt;br&gt;
ANSWER: 24&lt;br&gt;
For one way to set up and solve the problem using formal algebra....&lt;br&gt;
let x = Aaron&#39;s age now
then x+16 = Angela&#39;s age now&lt;br&gt;
x-8 = Aaron&#39;s age 8 years ago
(x+16)-8 = x+8 = Angela&#39;s age 8 years ago&lt;br&gt;
8 years ago, Angela&#39;s age was twice Aaron&#39;s age:
{{{x+8=2(x-8)}}}
{{{x+8=2x-16}}}
{{{x=24}}}&lt;br&gt;
ANSWER: Aaron&#39;s age now is x=24&lt;br&gt;
Here is another formal algebraic solution that is like the informal solution above.&lt;br&gt;
Let x = Aaron&#39;s age 8 years ago
Then 2x = Angela&#39;s age 8 years ago&lt;br&gt;
The difference in their ages is 16 years:
{{{2x-x=16}}}
{{{x=16}}}&lt;br&gt;
Aaron&#39;s age 8 years ago was x=16
Aaron&#39;s age now is 16+8=24&lt;br&gt;
Of the two algebraic solutions above, I personally prefer the latter, because the actual algebra is simpler.&lt;br&gt;
Look at both formal solutions, and at any others you might get in responses from other tutors, and find what &quot;works&quot; best for you.&lt;br&gt;
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