Question 1183172
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Find an equation of the line through the point (2,  -4) with slope -1/3

Use the point-slope formula:

{{{y - y[1] = m(x - x[1])}}}

{{{y - (-4) = expr(-1/3)(x - (2))}}}

{{{y + 4 = expr(-1/3)(x - 2)}}}

{{{y + 4 = expr(-1/3)x + 2/3}}}

{{{y = expr(-1/3)x + 2/3 - 4}}}

{{{y = expr(-1/3)x + 2/3 - 12/3}}}

{{{y = expr(-1/3)x - 10/3}}}

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Find an equation of the line through (2,  -7) and parallel to x+3=8

x+3=8 which simplifies to
  x=5 is a vertical line with no slope, so we need another vertical
line passing through (2,-7) which is just x = [the x-coordinate of (2,-7)]

Answer: x = 2

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Find the equation of the line that passes through the point (4, 6) and is perpendicular to the line x=-4 

x=-4 is a vertical line with no slope, so we just need a horizontal
line passing through (4,6) which is just y=the y-coordinate of (4,6)

Answer: y = 6

Edwin</pre>