Question 1183135
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An object is launched over level ground at 35 degrees above the horizontal 
with an initial speed of 52 m/s. What is the time of flight?
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<pre>
Calculate vertical component of the speed  {{{V[vert]}}} = 52*sin(35°)  meters per second.


Then the time flying up to the highest point is  t = {{{V[vert]/g}}}  seconds,   where g is the gravity acceleration.


The time falling dawn is the same value.


THREFORE, the total time of flight is  2t = {{{(2*V[vert])/g}}}.



All calculations are ELEMENTARY, so I leave them to you.
</pre>

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You are instructed.