Question 1183125
{{{4w=1976}}}

You can try using factorization of 1976, since it is a factor of 4.

{{{4w=494*4}}}

{{{log((4))+log((w))=log((494))+log((4))}}}

{{{log((w))=log((494))}}}
Which base you choose does not matter now.  It may as well be 10 for Common Logarithms.

{{{10^log((w))=10^log((494))}}}

{{{highlight(w=494)}}}