Question 1183085
<font color=black size=3>
To be really honest, I think the tutor @Theo is greatly overcomplicating things.


We simply need to graph *[Tex \Large y = sin(x)] and *[Tex \Large y = \sin^{-1}(x)] on the same xy axis when {{{0 <= x <= pi/2}}}


The graph of each function looks like this
<img src = "https://i.imgur.com/MNlNFpT.png">
The red graph is *[Tex \Large y = sin(x)] for the interval mentioned, and the blue graph *[Tex \Large y = \sin^{-1}(x)] is the result of reflecting the red curve over the dashed line y = x.


So we aren't considering the full *[Tex \Large y = \sin^{-1}(x)]  curve because it's missing the left half.


Unfortunately, the two curves overlap nearly perfectly when x gets closer to x = 0. This could lead to confusion. 


For the red sine curve, we have these properties:
Domain: {{{0 <= x <= pi/2}}} 
Range: {{{0 <= y <= 1}}} 


For the blue inverse sine curve, we have these properties
Domain: {{{0 <= x <= 1}}} 
Range: {{{0 <= y <= pi/2}}} 
The domain and range swap roles when going from the original function to the inverse.
</font>