Question 1183093
numbers are x, y, z
x+y=z+4
x+y+z=20; x+y+z=28
substitute
2z+4=20
z=8
z+4=12
so 2 integers whose sum is 12
5 and 7, with z=8
4 and 8, with z=8
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2z+4=28
z=12
x+y=16
0 and 16 works with z=12
1 and 15 works with z=12
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can set up for other integers between 20 and 28