Question 1183047
not sure if missing grouping symbols but in case  {{{8^(x-2)=2/25}}}



{{{log((8^(x-2)))=log((2/25))}}}

{{{(x-2)log((2^3))=log((2))-log((5^2))}}}

{{{x-2=(log((2))-2*log((5)))/(3*log((2)))}}}

{{{x=2+(log((2))-2*log((5)))/(3*log((2)))}}}

Computes to about 0.7854