Question 111508
THE THREE COSECUTIVE INTEGERS ARE X, X+1 & X+2.
(X+2)^2=(X+1)^2+76
X^2+4X+4=X^2+2X+1+76
4X-2X=-4+1+76
2X=73
X=73/2
X=36.5 
X+1=37.5 ANSWER FOR THE SECOND NUMBER
X=2=38.5 ANSWER FOR THE THIRD NUMBER.
PROOF
(38.5^2=37.5^2+76
1482.25=1406.25+76
1482.25=1482.25