Question 1183029
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Find the area of a parallelogram bounded by the y-axis, the line
x = 4,
the line
f(x) = 4 + 2x,
and the line parallel to f(x) passing through
(2, 6).
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<pre>
The line  f(x) = 4 + 2x  has  y-intercept of  f(0) = 4 + 2*0 = 4.


The line parallel to  f(x) = 4 + 2x  and passing through  (2,6)  is  y = Const + 2x

with Const = 6 - 2*2 = 2; so, the parallel line is  y = 2 + 2x,  and it has y-intercept of  y = 2.


Thus, our parallelogram has the base length of  4-2 = 2 units (along the y-axis) and the height of 4 units
(the distance from y-axis to vertical line x= 4).


THEREFORE, the area of our parallelogram is the product of the base and height measures, i.e. 2*4 = 8 square units.    <U>ANSWER</U>
</pre>

Solved.