Question 1182953
<br>
{{{f(x)=1/(x+1)}}}
{{{g(x)= x/(x-2)}}}<br>
f(x) = 10*g(x):<br>
{{{1/(x+1)=10(x/(x-2))}}}<br>
Multiply everything by the least common denominator<br>
{{{x-2=10x(x+1)}}}
{{{x-2=10x^2+10x}}}
{{{10x^2+9x+2=0}}}
{{{(5x+2)(2x+1)=0}}}<br>
x=-2/5 and x=-1/2<br>