Question 1182870

Answer

Given :
Mass {{{m=2.35kg}}}
{{{T[1]=20}}}  °C
{{{T[2]=83}}}  °C
Δ{{{T=83-20=63}}}  °C

{{{Q=m*C}}}*Δ{{{T}}}

where {{{C}}}= specific heat capacity of water ={{{4200J/(kgK)}}}

{{{Q=2.35*4200*63}}}

{{{Q=621810J}}}

{{{Q=621.810KJ}}}