Question 1182812
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            Edwin presented you a nice lecture.


&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;I, &nbsp;from my side, &nbsp;would like to comment what is written in &nbsp;<U>your post</U>.



<pre>
If you want to re-arrange your original equation to the form y = something, then your steps and your result should be as follows


    3x - 2y = 6

    3x - 6 = 2y   (you move the "6" from right side to the left side, changing the sign;

                   and you move "2y" from the left side to the right side, changing the sign).


Next, you divide the terms in the last equation by 2, and you get


    y = {{{(3/2)x -3}}}.


Everything is correct, but it is different from what is written in your post.
</pre>


&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;It is because what is written in &nbsp;<U>your post</U>&nbsp; is &nbsp;&nbsp;<U>W R O N G</U>.