Question 1182799
<pre>
{{{system(x+y=12,abs(x-y)<=2)}}}

y = 12-x

|x-(12-x)| ≤ 2

|x-12+x| ≤ 2

|2x-12| ≤ 2

2|x-6| ≤ 2

|x-6| ≤ 1

-1 ≤ x-6 ≤ 1
+6    +6  +6
------------
 5 ≤ x   ≤ 7

x = 5,6,7   
y = 7,6,5

3 ways.

Edwin</pre>