Question 1182745
normal is suitable
np=7 mean
np(1-p)=3.5=variance
sd=sqrt(V)=1.87
z <=(6.5-7)/1.87, using continuity correction factor
 z <=-0.5/1.87
=-0.2673
probability is 0.3946, using the normal approximation.
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The exact value is 0.3953