Question 1182808
1-sample proportion 99%CI z-int
half interval is z(0.995)+/- sqrt (p(1-p)/n)
=2.576*sqrt (0.65*0.35/351)
=0.0656 or 0.066
add to and subtract from mean
0.584 < p < 0.716.  The result may change slightly on how much z is rounded in the intermediate calculations. I took it to four decimal places.