Question 1182720
The following stages occur

1. steam 110 deg to steam 100 deg . Mass * specific heat *( T1-T2) . m * c * {{{(delta)}}}*T
300*2.08 *10

2. steam 100 deg to water 100 deg   Mass * latent heat of vaporization  m * l 
300*2236

3. Water 100 deg to water 0 deg  M * c *{{{(delta)}}} T  
300 *4.186 *100

4. water 0 deg to ice 0 deg   m * Latent heat of fusion
300 * 334


Latent heat of vapourization = 2236 joules/gm
Latent heat of fusion of ice = 334 joules/gram

specific heat of water 4.186 J/g°C
Specific heat of steam: 2.09 j/g deg C
Mass of steam = 300 grams

Use calci to calculate all 4 and add them up