Question 1182718
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The net force on a 2-kg body is 6 N. If the body is originally travelling with a velocity of 8 m/s, 
and if the force applied is opposite to the velocity, find the distance it will move before coming to rest.
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            We solve the problem and make calculations step by step.



<pre>
(1)  First we find the deceleration  "a"  by dividing the force by the mass (the second Newton's law)


         a = {{{F/m}}} = {{{6_N/2_kg}}} = 3 m/s^2.



(2)  Next we find the time to get the zero speed from the basic kinematic equation

         v = a*t,


where v is the initial velocity of 8 m/s (given) and "a" is the deceleration  a = 3 m/s^2, found above in step (1)


         t = {{{v/a}}} = {{{8/3}}} = 2.66666... seconds.



(3)   Finally, we find the distance


          d = {{{(a*t^2)/2}}} = {{{(3*(8/3)^2)/2}}} = {{{64/(2*3)}}} = {{{32/3}}} = 10 {{{2/3}}}  meters.      <U>ANSWER</U>
</pre>

Solved.