Question 111455
Factor:
{{{11x^2+11xy+13x+13y}}} Group the terms as follows:
{{{(11x^2+11xy)+(13x+13y)}}} From the first group, factor 11x and from the second group, factor 13.
{{{11x(x+y)+13(x+y)}}} Now factor the common factor of (x+y).
{{{(x+y)(11x+13)}}} This is called "factoring by grouping"