<PRE><B>Question 1182631</B>
Using synthetic division, find one zero of the polynomial f(x)=x^3+c^2-57x+135 
 I think this is: f(x) = x^3 + x^2 - 57x + 135
Try the lowest factor of 135, 3
:
.....___________________
 3 | 1 + 1 - 57 + 135
............3 + 12 - 135
....--------------------
......1 + 4 - 45 + 0
:
then write the polynomial in factored form based on the zero you found:
(x-3)(x^2 + 4x - 45)
Zero for the polynomial: f(__) = 0
Factor (x^2+4x-45):  (x+9)(x-5)
Factors of the polynomial based on the above zero: 
f(x)= (x-3)(x-5)(x+9)</PRE>