Question 1182546
Use sigma^2 for the distribution, since it is the variance, so  X~N(6.7, 3.24)
b. is not clear to me. The median weight is 6.7 kg, same as the mean for a normal distriution.
c. The median seedless watermelon weighing 7.8 kg from this distribution has a z-score of 
(7.8-6.7)/1.8=+0.6111
d. z > (6.2-6.7)/1.8 which is >-0.2778, and that z-score means a probability of 0.6094
e. z > (-0.4/1.8)=-0.222 and z < (0.3/1.8)=0.166667
that probability is 0.1541
f. z is 0.5244
0.5244=(x-6.7)/1.8
0.9439=x-6.7
x=7.6439 kg