Question 1182524
<font color=black size=3>
I'll show you how to do problems 1 and 5


Here's the z table I'm using
<a href = "https://www.ztable.net/">https://www.ztable.net/</a> 
You can use this one, some other similar online resource, or the z table in the back of your book.


===============================================================================

Problem 1


Using that table, you should find that
P(z < 0.66) = 0.74537
which is approximate
Note how we look at the 0.6 row and 0.06 column as shown below
<img src = "https://i.imgur.com/EoxhToE.png">
The value at the intersection of the row and column mentioned is what we're after.
In other words, z = 0.66 breaks up into 0.6 + 0.06


From there, we say
P(Z > 0.66) = 1 - P(Z < 0.66)
P(Z > 0.66) = 1 - 0.74537
P(Z > 0.66) = 0.25463


<font color=red>Answer: Approximately 0.25463</font>


Problems 3 and 4 will be handled in a similar fashion (with different numbers of course). 


Problem 2 will nearly be identical in steps, but you wont subtract from 1. You just simply need to copy a table value. 


For problems 2 and 3, make sure you use the negative z value portion of the table. 


===============================================================================


Problem 5


Using that same table, you should find
P(Z < -0.78) = 0.21770
P(Z < 0.56) = 0.71226
both values are approximate


Then we use the formula below
P(a < z < b) = P(z < b) - P(z < a)
P(-0.78 < z < 0.56) = P(z < 0.56) - P(z < -0.78)
P(-0.78 < z < 0.56) = 0.71226 - 0.21770
P(-0.78 < z < 0.56) = 0.49456


<font color=red>Answer: Approximately 0.49456</font>
</font>