Question 1182480
p(x=1) is e^(-lambda)*lambda^1/1
p(x=2) is e^(-lambda)*lambda^2/2
Those are equal, so 2lambda ^1=lambda^2
lambda=2
e^(-2)*2=e(-2)*2^2/2
mean is 2.
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probability x=3 is e^(-2)*8/6=0.1804