Question 1182488
Find the x- and y-intercepts of the graph of the equation.

1. 
{{{y = sqrt(2x - 1)}}}

set {{{y=0}}} to find x- intercept

0= sqrt(2x - 1)
0= 2x - 1
x = 1/2 =>x- intercept is at ({{{1/2}}},{{{0}}})

set {{{x=0}}} to find y-intercepts

{{{y = sqrt(2*0 - 1)}}}
{{{y = sqrt(- 1)}}}
{{{y = i}}}-> there is {{{no}}} y-intercepts


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(1/2,0,.12),locate(1/2,0.3,p(1/2,0)),
 graph( 600, 600, -10, 10, -10, 10, sqrt(2x - 1))) }}} 


2. 

{{{y = -abs(x + 10)}}}

set {{{y=0}}} to find x- intercept

{{{0= -abs(x + 10)}}}

{{{0=x + 10}}}

{{{-10=x }}}=>x- intercept is at ({{{-10}}},{{{0}}})

set {{{x=0}}} to find y-intercepts

{{{y = -abs(0 + 10)}}}
{{{y = -abs(10)}}}
{{{y = -10}}}=>y- intercept is at ({{{0}}},{{{-10}}})


{{{ graph( 600, 600, -20, 20, -20, 20, -abs(x + 10)) }}}