Question 111421
Everything is great until you reach the point where you factor out the leading coefficient (which you don't need to do). So I'm going to start off with the step that has {{{22r^2-1420r+6000=0}}}



*[invoke quadratic_formula 22, -1420, 6000, "r"]

note: ignore the graph. It didn't turn out the way I wanted it to.


Now notice that we get two answers. However if we subtract {{{50/11-10}}} (or 5.45-10) we get {{{50/11-10=-50/11}}} which is a negative number. So we must discard the second solution.


So her original speed was 60 mph and her slower speed was 50 mph