Question 1182467
{{{x^2+y^2=1 }}}
{{{x^2+y^2-6x+5=0 }}}
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{{{x^2+y^2-1 =0}}}
{{{x^2+y^2-6x+5=0}}}
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 the point of contact will be where

{{{x^2+y^2-1 =x^2+y^2-6x+5}}}.........simplify

{{{cross(x^2)+cross(y^2)-1 =cross(x^2)+cross(y^2)-6x+5}}}

{{{-1 =-6x+5}}}
{{{6x =1+5}}}
{{{6x =6}}}
{{{x=1}}}

go to

{{{x^2+y^2=1}}} ....substitute {{{x}}}

{{{1^2+y^2=1}}} 
{{{1+y^2=1 }}}
{{{y^2=1-1}}}
{{{y^2=0}}}
{{{y=0}}}

the point of contact will be at ({{{1}}},{{{0}}})


{{{ graph( 600, 600, -5, 5, -5, 5,sqrt(1-x^2), -sqrt(1-x^2), -sqrt(-x^2+6x- 5), sqrt(-x^2+ 6x-5)) }}}