Question 1182459
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Answers: 
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n+1 faces
2n edges
n+1 vertices
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Explanation:


The pyramid has an n-sided polygon as the base, where n is some positive whole number larger than 2. 


Let's say n = 5 and we have a pentagonal pyramid
There are n = 5 lateral sides (each lateral side a triangle), plus we have the base face as well on the bottom. That gives n+1 = 5+1 = 6 faces total


Going back to the general case, we would simply have n+1 faces.
n lateral faces, plus that 1 base face.


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Consider a triangular pyramid (n = 3) having 3 lateral edges that all meet at the apex or highest point of the pyramid.
Along the bottom there are n = 3 more edges.
Overall, this triangular pyramid has n+n = 3+3 = 6 edges.


In general, we have n+n = 2n edges.


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Along the bottom there are n vertices. At the very top is another vertex. So we have n+1 vertices overall.


We can use Euler's polyhedron formula
V - E + F = 2
to help confirm the answers above


V = number of vertices = n+1
E = number of edges = 2n
F = number of faces = n+1


So,
V - E + F = 2
n+1 - 2n + n+1 = 2
2 = 2
showing that everything works out
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