Question 1182358
x oz.*0.40 alcohol=0.40x oz pure alcohol
12 oz*0.45 alcohol=5.4 oz pure alcohol
(12+x) oz of 0.43 alcohol final solution is 5.16 +0.43x oz.
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Therefore, 0.40x+5.4=5.16+0.43x
0.03x=0.24
x=8 oz of 40% (3.2 oz pure)
12 oz of 45% (5.4 oz pure)
=20 oz 43% (8.6 oz pure)