Question 1182296
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Problem 1


There are 12 yellow out of 13+12+10+12+11 = 58 total.


This forms the fraction 12/58 = (2*6)/(2*29) = <font color=red>6/29</font> which is the probality of selecting a yellow skittle.


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Problem 2


We have 13 red + 11 purple = 24 skittles we want to select out of 58 total


24/58 = (2*12)/(2*29) = <font color=red>12/29</font> is the probability of selecting either a red or purple skittle (note the events are mutually exclusive).


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Problem 3


There are 10 green and 58-10 = 48 non-green skittles.


48/58 = (2*24)/(2*29) = <font color=red>24/29</font> is the probability of selecting a skittle that isn't green.


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Problem 4


This is assuming you aren't putting the first one back, or no replacement has been made. 


12/58 represents the probability of selecting an orange skittle (12 orange out of 58 total)


11/57 is the probability of selecting another orange skittle (12-1 = 11 orange left, out of 58-1 = 57 total left)


Multiply the probabilities
(12/58)*(11/57)
(12*11)/(58*57)
132/3306
<font color=red>22/551</font> is the probability of selecting two orange skittles in a row (no replacement).
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