Question 1182302
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Given triangle ABC, if csc A=13/7, then what is the exact value of cos A in fraction form. 
Include a labeled sketch.
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<pre>
If csc(A) = {{{13/7}}},  then  sin(A) = {{{7/13}}}  and  


    cos(A) = +/- {{{sqrt(1- (7/13)^2)}}} = +/- {{{sqrt(1- 49/169)}}} = +/- {{{sqrt((169-49)/169)}}} = +/- {{{sqrt(120)/13}}} = +/- {{{(2*sqrt(30))/13}}}.      <U>ANSWER</U>
</pre>

Solved.



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