Question 1182238
	percent	----------------	quantity												
Antifreeze	60	----------------			1.6	l									
water	0	----------------			x	l									
Mixture	8	----------------	1.6	+	x	l									
															
	0.6	*	1.6		+	0	x	=	0.08	(		1.6	+		x)
															
	0.96	+	0		x=	0.128		+		0.08	x)				
															
			-0.08		x=	0.128		-	0.96						
			-0.08		x=	-0.832		-							
					x=	10.4		liters	of water was there in the radiator

10.4+1.6 = 12 liters holding capacity