Question 111307
use the second equation to find y (y=6-2x) and then substitute this value into the first equation


(x+2)^2+(6-2x-2)^2=13 ___ x^2+4x+4+16-16x+4x^2=13 ___ 5x^2-12x+7=0 ___ (5x-7)(x-1)=0


plug the x values back into the second equation to find the corresponding y values ___ there will be two pairs


this is a line intersecting a circle (at two points)