Question 1182157
<br>
{{{f(x) = 3cos((1/2)x+90))-1}}}<br>
Rewrite the function so the coefficient on x is 1:<br>
{{{f(x) = 3cos((1/2)(x+180))-1}}}<br>
That is in the form<br>
{{{f(x) = a*cos(b(x-c))+d}}}<br>
In that form...<br>
a is the amplitude
b determines the period (the period (in degrees) is 360/b)
c is the horizontal shift (phase shift)
d is the vertical shift (determines the midline)<br>
So in this function...<br>
a is 3
b is 1/2; the period is 360/b = 360/(1/2) = 720 degrees
c is -180 degrees
d is -1<br>
ANSWERS:
amplitude 3
period 720 degrees
phase shift -180 degrees
midline y=-1<br>