Question 1182156
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Given the ratio 4 to 3...<br>
Let original length be 4x
Let original width be 3x<br>
That is a standard way to start work on a problem where a ratio is given.<br>
The increased length is 4x+5; the increased width is 3x+5.<br>
The original area is (4x)(3x); the new area is (4x+5)(3x+5).<br>
The increase in area is 200 (square inches):<br>
{{{(4x+5)(3x+5)-(4x)(3x) = 200}}}<br>
That equation simplifies to a linear equation (the x^2 terms cancel), so solving the problem from there should be easy.<br>
Remember when you solve the equation for x, that is not the answer to the problem; the answer is original length=4x and original width=3x.<br>