Question 1182137
this is a z-test
z=(x bar-mean)/sigma/sqrt(n)
=(34.1-34.5)/1.3/sqrt(6)
=-0.4*sqrt(6)/1.3
=-0.753
and similarly, z=0.7*sqrt(6)/1.3=1.319
the probability z is between those two values is 0.6806
or
calculator 2ndVARS2nnormal cdf(34.1,35.2,34.5,(1.3/sqrt(6)))
=0.6809 (less rounding so slightly more accurate.  Find out whether the z-value is to 2,3, or more decimal places.