Question 1182090

{{{(x+1)(x-2)+(x+2)(x+1)=2(3x-1)}}}.....expand

{{{x^2 - x - 2+x^2 + 3 x + 2=6x-2}}}

{{{2x^2 + 2x =6x-2}}}....simplify, both sides divide by {{{2}}}

{{{x^2 + x =3x-1}}}

{{{x^2 + x -3x+1=0}}}

{{{x^2  -2x+1=0}}}

use quadratic formula

{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}....in your case {{{a=1}}}, {{{b=-2}}}, {{{c=1}}}

{{{x = (-(-2) +- sqrt( (-2)^2-4*1*1 ))/(2*1) }}}

{{{x = (2)+- sqrt( 4-4 ))/2 }}}

{{{x = (2)+- sqrt( 0 ))/2 }}}

{{{x = (2)+- 0)/2 }}}

{{{x = 2/2 }}}

{{{x = 1 }}}