Question 1182091


{{{4x^2-2x-3=0 }}}....use quadratic formula


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}.... in your case {{{a=4}}}, {{{b=-2}}}, and {{{c=-3}}}

{{{x = (-(-2) +- sqrt( (-2) ^2-4*4*(-3)  ))/(2*4) }}}

{{{x = (2 +- sqrt( 4+48  ))/8 }}}

{{{x = (2 +- sqrt( 52 ))/8 }}}

{{{x = (2 +- 2sqrt(13))/8 }}}....simplify

{{{x = (1 +- sqrt(13))/4 }}}


exact solutions:

{{{x = 1/4 + sqrt(13)/4 }}}

{{{x = 1/4 - sqrt(13)/4 }}}

approximate solutions:

{{{x = 1.15}}}

{{{x =-0.65}}}