Question 1182089
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Please help with the homework. Solve the following using quadratic equation
(x+1)(x-2)+(x+2)(x+1)=2(3x-1)
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The left side is (trace my transformations)

      (x+1)*(x-2) + (x+2)(x+1) = take the common factor (x+1) out the parenteses = 

    = (x+1)*(x-2 + x+2) = (x+1)*(2x).



So, the equation takes the form

    2x*(x+1) = 2*(3x-1)


Cancel common factor 2 in both sides

    x*(x+1) = 3x-1


Simplify

    x^2 + x = 3x -1

    x^2 - 2x + 1 = 0

    (x-1)^2 = 0


The only solution is  x= 1.


<U>ANSWER</U>.  The given equation has a unique solution x= 1.
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Solved.